Notice that the sequence has a common difference of 6 units, then, using the following formula:
[tex]a_n=a_1+(n-1)d[/tex]where a1 is the first term and d is the common difference. Then, in this case we have the following:
[tex]\begin{gathered} d=6 \\ a_1=2 \\ \Rightarrow a_n=2+(n-1)\cdot6=2+6n-6 \\ =6n-4 \\ a_n=6n-4 \end{gathered}[/tex]therefore, the explicit rule is an=6n-4
