Given:
The mass of the object is,
[tex]m=60.986\text{ kg}[/tex]
The coefficient of friction is,
[tex]\mu=0.15[/tex]
The object is sliding on the horizontal surface at a uniform speed.
To find:
the force of friction exerted by the surface on the object
Explanation:
If we draw the free body diagram of the object we see,
The normal reaction is R, the applied force is F, and the frictional force isf.
As the object is continuing its constant speed, we can say the object is in equilibrium.
So,
[tex]R=mg[/tex]
and
[tex]\begin{gathered} f=F=\mu R \\ f=\mu mg \\ f=0.15\times60.986\times9.8 \\ f=89.649\text{ N} \end{gathered}[/tex]
Hence, the friction force exerted by the surface is 89.649 N.
