ical candidate has asked his/her assistant to conduct a poll to determine the percentage of people in the community that supports him/her. if the candidate wants a 1% margin of error at a 90% confidence level, what size of sample is needed? be sure to round accordingly.

A statistic called the margin of error measures the degree of random sampling error in a survey's findings. It states a probability that the outcome of a sample is likely to be close to the conclusion one would obtain if the entire population had been questioned. a figure derived from a random sample that indicates the likely magnitude of the sampling error in a population parameter estimate.

Given,

Margin of error = 0.01

Confidence level = 90%

Let proportion of people be 0.5

E = Z × √[tex]\frac{P(1-P)}{n}[/tex]

n = P(1-P) (Z/E)²

n = 0.5(1 - 0.5) (1.546/0.01)²

n = 6765.0625

n = 6765

The size of sample is 6765 if the candidate wants a 1% margin of error at a 90% confidence level.

To learn more about margin of error, visit:

https://brainly.com/question/10501147

#SPJ4