Answer:
27.95L
Explanations:
According to Charle's law, the volume of a given mass of a gas is directly proportional to absolute temperature provided that the pressure is constant. Mathematically;
[tex]\begin{gathered} V\alpha T \\ V=kT \\ k=\frac{V_1}{T_1}=\frac{V_2}{T_2} \end{gathered}[/tex]
where
V1 and V2 are the initial and final volume respectively
T1 and T2 are the initial and final temperature respectively (in Kelvin)
Given the following parameters
[tex]\begin{gathered} V_1=28.94L \\ T_1=20.0^0C+273=293K \\ T_2=10.0^0C+273=283K \end{gathered}[/tex]
Required
Final volume V₂
Substitute the given parameters into the formula to have:
[tex]\begin{gathered} V_2=\frac{V_1T_2}{T_1} \\ V_2=\frac{28.94\times283}{293} \\ V_2=\frac{8190.02}{293} \\ V_2=27.95L \end{gathered}[/tex]
Hence the new volume of the neon gas is 27.95L
