Explanation:
The heat flow can be calculated as
[tex]Q=kA\frac{T_1-T_2}{L}[/tex]Where k is the thermal conductivity, A is the area, T1 is the temperature of the ice water, T2 is the temperature of the room, and L is the thickness.
Replacing k = 0.01 J/(s m °C), A = 0.950 m², T1 = 0°C, T2 = 35 °C and L = 2.50 cm = 0.025 m, we get
[tex]\begin{gathered} Q=(0.01\frac{J}{s\text{ m }\degree C})(0.95\text{ m}^2)\frac{0\degree C-35\degree C}{0.025\text{ m}} \\ \\ Q=-13.3\text{ W} \end{gathered}[/tex]Therefore, the heat flow through the walls is 13.3 W.
The negative sign indicates the direction of the heat flow, in this case, the heat goes to the water.
