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the point Q lies on the curve f(x) = -x^2 + 6x-7 and has coordinates (4,1)Line L, through Q, is perpendicular to the tangent at Q1) Find the coordinates of the point on the graph of f(x) = x^2-x at which the tangent is parallel to the line y=5x

Respuesta :

Point 1 Is Q

Find tangent parallel to y = 5x

Then

Slope m= 5

FOR F(x) = x^2 - x , tangent slope = 2x - 1

Then write

2x - 1 = 5

x= (1+5)/2 = 3

Then find Y = x^2 - x = 3^2 - 3 = 6

So then ANSWER IS

Coordinates of point tangent parallel are

(3, 6)