Answer
126.83 K (-231.1 farenheit)
Explanation
The given critical temperature of the three substances are:
93.0 K, -250.0 celsius and -231.1 farenheit.
To know which of these conductors has the highest Tc, value, you need to convert the given critical temperatures to kelvin
Conversion of -350.0 celsius to kelvin.
From celsius to kelvin, add 273 K, that is
[tex]\begin{gathered} 0^0C+273=273K^{} \\ \text{Therefore,} \\ -250.0\text{ celsius }=-250.0+273=23.0K \end{gathered}[/tex]
Conversion of -231.1 farenheit to kelvin.
From farenheit to kelvin, use the conversion formula below:
[tex]\begin{gathered} \frac{5}{9}(^0F-32)+273=K \\ \text{Hence, } \\ -231.1\text{ farenheit }=\frac{5}{9}(-231.1-32)+273 \\ =\frac{5}{9}(-263.1)+273 \\ =-146.17+273 \\ =126.83K \end{gathered}[/tex]
So, the critical temperature of the three substances in kelvin are:
93.0 K, 23.0 K and 126.83 K.
Hence, the conductors that has the highest Tc, value is 126.83 K (-231.1 farenheit).
