Let the number of pants bought be p and the number of shirts bought be s
• Each pant costs $8.99 and ,p, pants would cost
• Each shirt costs $3.99 and ,s, shirts would cost
The total budget is at max $60, so we can write the inequality:
[tex]8.99p+3.99s\leq60[/tex]-------------->>>>>>>>>>>>> First, let's find the s-intercept by putting p = 0:
[tex]\begin{gathered} 8.99p+3.99s\leq60 \\ 8.99(0)+3.99s\leq60 \\ 3.99s\leq60 \\ s\leq\frac{60}{3.99} \\ s\leq15.03 \end{gathered}[/tex]Rounding to a whole number,
[tex]s\leq15[/tex]-------------->>>>>>>>>>>>> Then, let's find the p-intercept by putting s = 0:
[tex]\begin{gathered} 8.99p+3.99s\leq60 \\ 8.99p+3.99(0)\leq60 \\ 8.99p\leq60 \\ p\leq\frac{60}{8.99} \\ p\leq6.67 \end{gathered}[/tex]