What is the surface area of the rightcone?26 cm24 cmA 260π cm²2B 340 cm²10 cmC 360 cm²D 6240 cm²

Given:
• Height of cone = 24 cm
,• Radius of cone = 10 cm
,• Slant height = 26 cm
Let's find the surface area of the right cone.
To find the surface area of the cone, apply the formula:
[tex]SA=\pi rs+\pi r^2[/tex]Where:
s is the slant height
r is the radius
Thus, we have:
[tex]\begin{gathered} SA=(\pi *10*26)+(\pi *10^2) \\ \\ SA=260\pi+100\pi \\ \\ SA=360\pi\text{ cm}^2 \end{gathered}[/tex]Therefore, the surface area of the cone is 360π cm².
ANSWER:
C. 360π cm².