just need help solving this ( not graded just a review)

Given
jenny mixed 4kg of mixed nuts containing 16% of peanuts with 12kg of mixed nuts containing 40% of peanuts .
Find
Percent in the new mixture of peanuts
Explanation
we are given 4kg of mixed nuts containing 16% of peanuts
Amount of quantity =
[tex]\frac{percentage}{100}\times totalamount[/tex]so,
[tex]\frac{16}{100}\times4=0.64kg[/tex]and also 12kg of mixed nuts containing 40% of peanuts .
so,
[tex]\frac{40}{100}\times12=4.8kg[/tex]so,total weight
[tex]0.64+4.80=5.44kg[/tex]let total mass pf mixture containing x % peanuts.
so,
[tex]\begin{gathered} \frac{5.44}{16}=\frac{x}{100} \\ 34=x \end{gathered}[/tex]Final Answer
Percent in the new mixture of peanuts = 34%