[tex]\begin{gathered} \text{Statement }\rightarrow\text{ Reason} \\ 7(x-1)=2(3x-2)\text{ }\rightarrow Given \end{gathered}[/tex][tex]7x-7=6x-4\text{ }\rightarrow\text{ Distributive property}[/tex]
Beacuse to both sides of the equation you distribute the number that is outside the parentheses when making the product.
Then, you operate on both sides of the equation -7x, that is, you use the additive inverse of 7x
[tex]\begin{gathered} 7x-7-7x=6x-4-7x \\ -7=-1x-4\text{ }\rightarrow\text{ additive inverse property} \\ \end{gathered}[/tex]
Then, you operate on both sides of the equation 4, that is, you use the add inverse of -4
[tex]\begin{gathered} -7=-1x-4 \\ -7+4=-1x-4+4 \\ -3=-1x\text{ }\rightarrow\text{ additive inverse property} \end{gathered}[/tex]
Finally,
[tex]\begin{gathered} -3=-1x \\ \frac{-3}{-1}=x\text{ }\rightarrow\text{ Division property} \\ 3=x\text{ }\rightarrow\text{ Reflexive property} \end{gathered}[/tex]
