The equation of a circle with Center (h,k) and Radius = r is given by,
[tex](x-h)^2+(y-k)^2=r^2[/tex]
In our question, we are given,
Center = (-6, 8)
Radius = 11
We can substitute and figure out the equation of the circle as,
[tex]\begin{gathered} (x-(-6))^2+(y-8)^2=11^2 \\ (x+6)^2+(y-8)^2=121 \end{gathered}[/tex]Answer[tex](x+6)^2+(y-8)^2=121[/tex]
