Given:
You will spin the spinner twice in which there are 4 boxes with numbered
[tex]2,\text{ }3,\text{ }4,\text{ and }5.[/tex]Required:
We have to find the probability of landing on a number greater than 3 and then landing on a number less than 5 in percentage.
Explanation:
There are two possibilities of landing on a number greater than 3 which are 4 and 5.
The total number of possibilities when spinning the spinner is 4.
Hence the probability of landing on a number greater than 3 is
[tex]\frac{2}{4}=\frac{1}{2}[/tex]Since the events are independent. The possibility of landing a number less than 5 the second time is 2, 3, and 4.
Hence the probability of landing on a number less than 5 is
[tex]\frac{3}{4}[/tex]Therefore the required probability of landing on a number greater than 3 and then landing on a number less than 5 is
[tex]\frac{1}{2}\times\frac{3}{4}=\frac{3}{8}[/tex]Hence the required percentage is
[tex]\frac{3}{8}\times100=37.5\%[/tex]Final answer:
Hence the final answer is
[tex]\begin{equation*} 37.5\% \end{equation*}[/tex]
