Given:
The primary coil of the transformer has 660 turns. Thus, Np = 600.
The primary voltage of the transformer is: Vp = 4840 v
The secondary voltage of the transformer is: Vs = 220 v
To find:
The number of turns of the secondary coil (Ns).
Explanation:
The primary voltage Vp, secondary voltage Vs, a number of turns on primary coil Np and on secondary coil Ns are related as:
[tex]\frac{V_p}{V_s}=\frac{N_p}{N_s}[/tex]Rearranging the above equation, we get:
[tex]N_s=N_p\frac{V_s}{V_p}[/tex]Substituting the values in the above equation, we get:
[tex]\begin{gathered} N_s=660\times\frac{220\text{ v}}{4840\text{ v}} \\ \\ N_s=\frac{145200}{4840} \\ \\ N_s=30 \end{gathered}[/tex]Final answer:
The number of turns on the secondary coil of the given step-down transformer is 30.
