Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.Match each equation to the line of best fit that it models.





Consider the individual graph.
1)
Given:
We get the points (0,2) and (7,3) that lie on the best fit from the graph.
Required:
We need to find the equation of the line.
Explanation:
Recall that the y-intercept is the point where the line crosses the y-axis.
At (0,2), the line crosses the y-axis.
The y-intercept, b= 2.
Consider the line equation.
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept.
Substitute b =2 in the equation.
[tex]y=mx+2[/tex]Substitute x =7 and y =3 in the equation to find the value of m.
[tex]3=m(7)+2[/tex]Solve for m.
[tex]3-2=7m[/tex][tex]m=\frac{1}{7}[/tex]Substitute m=1/7 and b =2 in the line equation.
[tex]y=\frac{1}{7}x+2[/tex]Answer:
[tex]y=\frac{1}{7}x+2[/tex]2)
Given:
We get the points (0,2) and (7,6) that lie on the best fit from the graph.
Required:
We need to find the equation of the line.
Explanation:
Recall that the y-intercept is the point where the line crosses the y-axis.
At (0,2), the line crosses the y-axis.
The y-intercept, b= 2.
Consider the line equation.
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept.
Substitute b =2 in the equation.
[tex]y=mx+2[/tex]Substitute x =7 and y =6 in the equation to find the value of m.
[tex]6=m(7)+2[/tex]Solve for m.
[tex]6-2=7m[/tex][tex]m=\frac{4}{7}[/tex]Substitute m=4/7and b =2 in the line equation.
[tex]y=\frac{4}{7}x+2[/tex]Answer:
[tex]y=\frac{4}{7}x+2[/tex]3)
Given:
We get the points (0,2) and (7,1) that lie on the best fit from the graph.
Required:
We need to find the equation of the line.
Explanation:
Recall that the y-intercept is the point where the line crosses the y-axis.
At (0,2), the line crosses the y-axis.
The y-intercept, b= 2.
Consider the line equation.
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept.
Substitute b =2 in the equation.
[tex]y=mx+2[/tex]Substitute x =7 and y =1 in the equation to find the value of m.
[tex]1=m(7)+2[/tex]Solve for m.
[tex]1-2=7m[/tex][tex]m=\frac{-1}{7}[/tex]Substitute m= -1/7and b =2 in the line equation.
[tex]y=\frac{-1}{7}x+2[/tex]Answer:
[tex]y=\frac{-1}{7}x+2[/tex]4)
Given:
We get the points (0,2) and (6.7) that lie on the best fit from the graph.
Required:
We need to find the equation of the line.
Explanation:
Recall that the y-intercept is the point where the line crosses the y-axis.
At (0,2), the line crosses the y-axis.
The y-intercept, b= 2.
Consider the line equation.
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept.
Substitute b =2 in the equation.
[tex]y=mx+2[/tex]Substitute x =6 and y =7 in the equation to find the value of m.
[tex]7=m(6)+2[/tex]Solve for m.
[tex]7-2=6m[/tex][tex]m=\frac{5}{6}[/tex]Substitute m= 5/6 and b =2 in the line equation.
[tex]y=\frac{5}{6}x+2[/tex]Answer:
[tex]y=\frac{5}{6}x+2[/tex][tex]y=\frac{5}{6}x+2[/tex]