The diameter of the circular hot tub, D=5.4 m.
The width of the circular deck, t=2.2 m.
The radius of the hot tub is,
[tex]r=\frac{D}{2}=\frac{5.4}{2}=2.7[/tex]
The radius of the circular deck,
[tex]R=r+t=2.7+2.2=4.9[/tex]
The area of the deck can be calculated as,
[tex]\begin{gathered} A=\pi(R^2-r^2) \\ A=\pi(4.9^2-2.7^2) \\ A=3.14\times(24.01-7.29) \\ A=52.5m^2 \end{gathered}[/tex]
Therefore, the area of the deck is 52.5 square meters.
