Given:
a.) The width of the rectangle is 0.7 meters less than the length.
b.) The perimeter of a rectangle is 44.6 meters.
First, let's draw the rectangle to better understand the problem.
Recall: The formula in getting the perimeter of the rectangle.
[tex]\text{ Perimeter = 2Length + 2Width}[/tex]
But it stated that the width of the rectangle is 0.7 meters less than the length.
Thus,
Width = Length - 0.7
Let's now find its Length,
[tex]\begin{gathered} \text{ Perimeter = 2Length + 2Width} \\ \text{ 44.6 = 2Length + 2(Length - 0.7)} \\ \text{ 44.6 = 2Length + 2Length - 1.4} \\ \text{ 44.6 + 1.4 = 4Length} \\ \text{ 46 = 4Length} \\ \text{ 4Length = 46} \\ \text{ }\frac{\text{4Length}}{\text{ 4}}\text{ = }\frac{\text{ 46}}{\text{ 4}} \\ \text{ Length = }11.5\text{ meters} \end{gathered}[/tex]
Therefore, the length of the rectangle is 11.5 meters.
Let's now determine the width,
Width = Length - 0.7
= 11.5 - 0.7
Width = 10.8 meters
Therefore, the width of the rectangle is 10.8 meters.
