Answer:[tex]\frac{8C4}{11C4}=0.212[/tex]
Explanation:
By definition,
[tex]\text{nCr}=\frac{n!}{(n-r)!r!}[/tex]
Using this, we have:
[tex]\begin{gathered} 8C4=\frac{8!}{(8-4)!4!}=\frac{40320}{576}=70 \\ \\ \\ 11C4=\frac{11!}{(11-4)!4!}=\frac{39916800}{120960}=330 \\ \\ \frac{8C4}{11C4}=\frac{70}{330}=\frac{7}{33}=0.212 \end{gathered}[/tex]
