I need help with the work question 8Area of Regular PolygonsFind the area of each regular polygon. Leave your answer in simplest form. Ok

The area os any regular polygon is given by:
[tex]A=\frac{1}{2}Pa[/tex]where P is the perimeter and a is the apothem. The perimeter of a regular polygon is given by:
[tex]P=ns[/tex]where n is the number of sides and s is the length of its side. In this case we have a triangle, then n=3; we also know the length of the side, plugging these values we have:
[tex]\begin{gathered} P=(3)(28\sqrt{3}) \\ P=84\sqrt{3} \end{gathered}[/tex]Plugging the value of the perimeter and the apothem on the expression for the area we have:
[tex]\begin{gathered} A=\frac{1}{2}(84\sqrt{3})(14) \\ A=588\sqrt{3} \end{gathered}[/tex]Therefore, the area of the triangle is:
[tex]A=588\sqrt{3}[/tex]This is approximately 1018.4 square units