From the first table, we have;
Given that;
[tex]f(x)=b^x[/tex]
But, table II gives;
Given that;
[tex]g(x)=\log _b(x)[/tex]
Where b is same positive constant for both equations.
Recall from a law of logarithm that;
[tex]\text{If }\log _ba=c,\Leftrightarrow a=b^c[/tex]
Thus;
[tex]\begin{gathered} g(x)=\log _b(x) \\ x=b^{g(x)} \\ \end{gathered}[/tex][tex]f(x)=7,x=1.404[/tex]
Also;
from the second table;
[tex]x=10,g(x)=1.661[/tex]
