We will use the formula of the distance between 2 points
[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]We have
(2,3)=(x1,y1)
we can assume
(1,y)=(x2,y2)
[tex]\begin{gathered} 5=\sqrt[]{(1-2)^2+(y-3_{})^2} \\ 5=\sqrt[]{1+(y-3)^2} \\ 5^2=1+(y-3)^2 \\ 5^2-1=(y-3)^2 \\ 24=(y-3)^2 \\ \sqrt[]{24}=y-3 \\ We\text{ have two solutions} \\ y=3-2\sqrt[]{6}=-1.89 \\ y=3+2\sqrt[]{6}=7.89 \end{gathered}[/tex]the two points that we can obtain
(1,-1.89) distance from (2,3) is 5
(1,7.89) distance from (2,3) is 5
