[tex]\begin{gathered} \Rightarrow\frac{x-3}{4}+\frac{2}{3}=\frac{17}{12} \\ \Rightarrow\frac{3x-9+8}{12}=\frac{17}{12} \\ \Rightarrow3x-1=17 \\ \Rightarrow3x=18 \\ \Rightarrow x=6 \end{gathered}[/tex][tex]\begin{gathered} \frac{3x}{4}+2=\frac{5x}{4}-6 \\ 2+6=\frac{5x}{4}-\frac{3x}{4} \\ 8=\frac{2x}{4} \\ x=16 \end{gathered}[/tex]
