Given:The given data is (in inches)
9.6, 9.8, 10.2, 9.8, 9.7, 8.9, 10.3, 9.9, 9.3, 10.2, 10.2.
Required:
(a) Mean
(b) Median
(c) Mode
(d) Mid-Range
Explanation:
Let us first arrange the data in ascending order
8.9, 9.3, 9.6, 9.7, 9.8, 9.8, 9.9, 10.2, 10.2, 10.2, 10.3
(a) Mean
The mean of data is sum of observations divided by number of observations
[tex]\begin{gathered} Mean=\frac{8.9+9.3+9.6+9.7+9.8+9.8+9.9+10.2+10.2+10.2+10.3}{11} \\ Mean=9.809 \end{gathered}[/tex]
(b) Median
Since there are 11 terms, so median is
[tex]\frac{11+1}{2}=\frac{12}{2}=6th\text{ term}[/tex]
So median is
[tex]Median\text{ = }9.8[/tex]
(c) Mode
Mode is most occured frequency
so here 10.2 occurs most of the time (3 times)
[tex]Mode=10.2[/tex]
(d) Mid range
Mid range is average of least and highest frequency
[tex]Mid\text{ range = }\frac{8.9+10.3}{2}=9.2[/tex]
Final Answer:
(a) Mean = 9.809
(b) Median = 9.8
(c) Mode = 10.2
(d) Mid range = 9.2