A 150 mH inductor is is a circuit with a 60 Hz voltage source and a current of 1.6 A is measured on a VOM. What is the phase angle between the current and the voltage?

Respuesta :

Given:

The inductance is,

[tex]L=150\text{ mH}[/tex]

The current is,

[tex]i=1.6\text{ A}[/tex]

The frequency of the current is,

[tex]f=60\text{ Hz}[/tex]

To find:

The phase angle between the current and the voltage

Explanation:

The phase angle between the current and the voltage is,

[tex]\Phi=tan^{-1}\frac{X_L}{R}[/tex]

As the circuit is purely inductive,

[tex]R=0[/tex]

The phase angle is,

[tex]\begin{gathered} \Phi=tan^{-1}\frac{2\pi fL}{0} \\ \Phi=90\degree \end{gathered}[/tex]

Hence, the phase angle is 90 degrees.