It is given that the line passes through points (x1, y1)=(2, -3) and (x2, y2)=(4, 5).
The two point form of the equation of a line is given by,
[tex]y-y1=\frac{y2-y1}{x2-x1}(x-x1)[/tex]Substitute the known values to obtain the equation of the line.
[tex]\begin{gathered} y-(-3)=\frac{5-(-3)}{4-2}(x-2) \\ y+3=\frac{8}{2}(x-2) \\ y+3=4(x-2) \\ y+3=4x+4\times(-2) \\ y+3=4x-8 \\ y=4x-8-3 \\ y=4x-11 \end{gathered}[/tex]Therefore, the equation of the line is y=4x-11.
