Respuesta :
Given data
*The given depth is h = 15.2 m
*The given atmospheric pressure is P_atm = 101 kPa
*The value of the density of freshwater is D_w = 1000 kg/m^3
*The value of the acceleration due to the gravity is g = 9.8 m/s^2
The expression for the absolute pressure (in kilopascals) experienced by the diver is given as
[tex]P_{abs}=P_{atm}+D_wgh[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} P_{abs}=101+(1000\times9.8\times15.2) \\ =101+(148960\text{ Pa)} \\ =101\text{kPa}+148.96\text{ kPa} \\ =249.6\text{ kPa} \end{gathered}[/tex]Hence, the absolute pressure (in kilopascals) experienced by the diver is P_abs = 249.6 kPa
As from the given data, the dimension of a solid aluminum bar is 0.520 m by 0.540 m by 0.950 m, then the buoyant force experienced by the bar is calculated as
[tex]F_b=D_wVg[/tex]*Here V is the volume of the bar
Substitute the known values in the above expression as
[tex]\begin{gathered} F_b=(1000)(0.520\times0.540\times0.950)(9.8) \\ =2614.24\text{ N} \end{gathered}[/tex]Hence, the buoyant force experienced by the bar is F_b = 2614.24 N
