Given:
[tex]f(x)=-x^2+4x[/tex]
Opens downward.
[tex]f(x)=-x^2+4x-4+4[/tex][tex]f(x)=-(x^2-4x+4)+4[/tex][tex]f(x)=-(x-2)^2+4[/tex]
Vertex of the parabol is (2,4)
Line of symmetry:
[tex]x=2[/tex]
Y-intercept:
[tex]f(0)=4[/tex]
y=4 is the y intercept.
[tex]\Rightarrow(0,0)[/tex]
Strategic points are :
[tex](2,4),(0,0),(4,0)[/tex]
