[tex]\begin{gathered} f(x)=3x-6 \\ \\ h(x)=\frac{x+6}{3} \end{gathered}[/tex]
first we make (foh)(x)
[tex]foh(x)=3(\frac{x+6}{3})-6[/tex]
simplify
[tex]\begin{gathered} foh(x)=x+6-6 \\ foh(x)=x \end{gathered}[/tex]
now replace x=6
[tex]foh(6)=(6)[/tex]
So, the composite function (foh) evaluated at x=6 is,(foh)(6)=6
