The formula we are going to use is:
[tex]\rho=\frac{m}{V}[/tex]Where
p is density, in g/mL
m is mass, in grams
V is volume, in mL or cm^3
Density is given and we have to find the volume.
The gold bar is in a shape of rectangular prism, so we need to multiply the width, height, and length (given) of the gold bar to find its volume. Let's do it:
[tex]\begin{gathered} V=1.2\times1.6\times23 \\ V=44.16\operatorname{cm}^3 \end{gathered}[/tex]Now, we substitute and solve for m, the mass (weight) in grams:
[tex]\begin{gathered} \rho=\frac{m}{V} \\ 19.3=\frac{m}{44.16} \\ m=19.3\times44.16 \\ m=852.288\text{grams} \end{gathered}[/tex]The mass is abut 852.29 grams