To answer this, we will need to select 2 of the 3 possible cities in question 3C2:
[tex]\begin{gathered} \frac{3!}{2!1!}=3 \\ \text{Total possibilities = 2}^3=8 \\ \text{Probability = 3/8} \end{gathered}[/tex]So, the probability that any two cities have the same combination in a game is 3/8.
