Let the number of antifreeze gallon is x
Since the solution contains 95% pure antifreeze, then multiply x by 95% after changing it to decimal
[tex]x\times\frac{95}{100}=0.95x[/tex]Since they need 285 gallons containing 20% pure antifreeze, then multiply 285 by 20%
[tex]285\times\frac{20}{100}=57[/tex]Equate 0.95x by 57
[tex]0.95x=57[/tex]Divide both sides by 0.95
[tex]\begin{gathered} \frac{0.95x}{0.95}=\frac{57}{0.95} \\ x=60 \end{gathered}[/tex]Subtract 60 from 285
[tex]285-60=225[/tex]They need 225 gallons of water and 60 gallons of premium antifreeze to mixe them
Water: 225 gallons
Premium antifreeze: 60 gallons
