The total momentum after collision = 60 kgm/s
Explanation:[tex]\begin{gathered} \text{Mass of Matt, m}_m=\text{ 80kg} \\ \text{Mass of Trey, m}_t=\text{ 90 kg} \end{gathered}[/tex]Before the collision:
Matt was moving 3 m/s to the east and Trey was moving 2 m/s to the west
[tex]\begin{gathered} \text{Initial speed of Matt, u}_m=\text{ 3m/s} \\ \text{Initial speed of Trey, u}_t=\text{ -2m/s (Since it is an opposite direction)} \end{gathered}[/tex]According to the principle of momentum conservation:
The total momentum before collision = The total momentum after collision
[tex]\begin{gathered} \text{Total momentum before collision = m}_mu_m+m_tu_t \\ \text{Total momentum before collision = 80(3) + 90(-2)} \\ \text{Total momentum before collision = 240 - 180} \\ \text{Total momentum before collision = 60 kgm/s} \end{gathered}[/tex]Since the total momentum before collision = Total momentum after collision
The total momentum after collision = 60 kgm/s
