Respuesta :

[tex]y=(x+5)(x+4)[/tex]

start by writing the equation in standard form

[tex]\begin{gathered} y=x^2+4x+5x+20 \\ y=x^2+9x+20 \end{gathered}[/tex]

find the vertex of the equation (h,k), in which

[tex]\begin{gathered} h=(-\frac{b}{2a}) \\ k=f(-\frac{b}{2a}) \end{gathered}[/tex]

find h

[tex]\begin{gathered} h=-\frac{9}{2\cdot1} \\ h=-4.5 \end{gathered}[/tex]

find the value of k

[tex]\begin{gathered} k=(-4.5)^2+9\cdot(-4.5)+20 \\ k=-0.25 \end{gathered}[/tex]

after having the vertex, write the equation in vertex form

[tex]y=(x+4.5)^2-0.25[/tex]