To solve this problem, we could use the following model
[tex]p(t)=p_0(1+r)^t[/tex]Where p0 represents our population in millions, r represents the growth rate, and t represents the amount of years after 2011( 2011 is t = 0).
We have all of our values
[tex]\begin{gathered} p_0=149 \\ r=0.01521 \\ t=2019-2011=8 \end{gathered}[/tex]Plugging those values in our model, we have
[tex]p(8)=149(1+0.01521)^8=168.125413042\ldots\approx168.13[/tex]Then, the size of the population in 2019 will be about 168.13 million.