Explanation
From the diagram
[tex]\begin{gathered} radius\text{ of cicle =}PB=PD=3 \\ PC=PD+DC=3+2=5 \end{gathered}[/tex]
Therefore;
[tex]\begin{gathered} PC^2=PB^2+BC^2 \\ 5^2=3^2+BC^2 \\ 25=9+BC^2 \\ BC^2=25-9 \\ BC^2=16 \\ BC=\sqrt{16} \\ BC=4 \end{gathered}[/tex]
Answer: Option A
