we have the following data set
We can plot then in the cartesian plane,
we can calculate the line of best fit be using the extreme points,
[tex]\begin{gathered} (x1,y1)=(1.0,1.1) \\ (x2,y2)=(8.3,22.1) \\ y-y1=\frac{y2-y1}{x2-x1}*(x-x1) \end{gathered}[/tex]
replacing and solving:
[tex]\begin{gathered} y-1.1=\frac{22.1-1.1}{8.3-1.0}*(x-1.0) \\ y-1.1=\frac{21}{7.3}x-\frac{21}{7.3} \\ y=\frac{210}{73}x-\frac{1297}{730} \\ y\approx2.6-0.4 \end{gathered}[/tex]
Thus, the answer is y = 2.6x - 0.4
