hello
to solve this problem, let's identify the functions first
[tex]h(t)=2t+1[/tex][tex]g(t)=2t+2[/tex][tex]h-g(t)=\text{ ?}[/tex][tex]\begin{gathered} h-g(t)=(2t+1)-(2t+2)_{} \\ h-g(t)=2t+1-2t-2 \\ h-g(t)=0-1 \\ h-g(t)=-1 \end{gathered}[/tex]the answer to this question is -1
