[tex]\begin{gathered} The\text{ inequality is,} \\ y<3x-4 \\ \text{Make ithis equation as equality equation} \\ y=3x-4 \\ \text{Substitute x=0} \\ y=3\times0-4 \\ y=-4 \\ So,\text{ the point is (0,-4)} \\ \text{Now, substitute y=0} \\ 0=3x-4 \\ x=\frac{4}{3} \\ so,\text{ the point is,} \\ (\frac{4}{3},0) \\ So\text{ the }line\text{ passes through the }(0,-4),and(\frac{4}{3},0)_{} \\ (0,-4)\Rightarrow IV\text{ quardent} \\ (\frac{4}{3},0)\Rightarrow I\text{ quardent} \\ \text{If we extend this line it will passes through also II quardent} \\ So,\text{ the only III quardent does not have solution.} \\ \text{Thus, the option (C) is correct.} \end{gathered}[/tex]
