The given equation is already in Vertex From:
[tex]\text{ y = }a(x-h)^2\text{ + k}[/tex]Therefore, it'll be easy for us to state the vertex.
From the given equation:
[tex]\text{ y = }a(x-h)^2\text{ + k }\rightarrow y=-(x+3)^2\text{ + 5}[/tex]a = - 1
h = - 3
k = 5
Therefore, the vertex = (h,k) = (-3,5) at maximum value.
