In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
day 1 = 3,500 ants
day 2 = 7,000 ants
day 3 = 14,000 ants
geometric sequence.
day 5 = a5 = ?
Step 02:
geometric sequence
an = a1 * r ^ (n - 1)
a1 = 3500
a2 = 7000
r = a2 / a1 = 7000/3500 = 2
an = a1 * r ^ (n - 1)
n = 5
a5 = 3500 * 2 ^ ( 5 - 1)
a5 = 3500 * 16 = 56000
The answer is:
The population of ants on day 5 is 56000.
