Arrange the following inequality into slope-intercept form. Then describe what type of boundary line would be used.

Answer:
The inequality is given below as
[tex]6x>2y-5[/tex]Step 1:
Concept:
The slope-intercept form is given below as
[tex]\begin{gathered} y=mx+c \\ m=slope \\ c=y-intercept \end{gathered}[/tex]To put the inequality in slope-intercept form, we will make y the subject of the formula
[tex]\begin{gathered} 6x\gt2y-5 \\ -2y>-6x-5 \\ divide\text{ all through by -2} \\ \frac{-2y}{-2}\gt\frac{-6x}{-2}\frac{-5}{-2}(the\text{ inequality sign reverses\rparen} \\ y<3x+\frac{5}{2} \end{gathered}[/tex]Hence,
By rearranging it in slope-intercept form, we will have the inequality be
[tex]\Rightarrow y\lt3x+\frac{5}{2}[/tex]Step 2:
Describe the type of boundary lines to be used
Boundary lines in math are the same: they identify the outer edge (or outline) of a shape or area. This could be a geometric shape or an inequality graph.
The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality. The boundary line is dashed for > and < and solid for ≤ and ≥.
Hence,
The boundary line to be used will be DASHED
Step 3:
Determine where to be shaded
The inequality in slope-intercept form is given below as
[tex]\operatorname{\Rightarrow}y\lt3x+\frac{5}{2}[/tex]Shade the appropriate region. Unless you are graphing a vertical line the sign of the inequality will let you know which half-plane to shade. If the symbol ≥ or > is used, shade above the line. If the symbol ≤ or < is used shade below the line.
Graphically,
Hence,
The sign used in the inequality here is <.
Therefore,
We will have to SHADE BELOW THE LINE