To answer this question we have to evaluate the given equation using each ordered pair and see if it's true:
(0, sqrt(13))
[tex]\begin{gathered} (0-2)^2+(\sqrt[]{13})^2=13 \\ 4+13=13 \\ 17\ne13 \end{gathered}[/tex]
This point does not lie on the circle.
(0, -sqrt(13))
[tex]\begin{gathered} (0-2)^2+(-\sqrt[]{13})^2=13 \\ 4+13=13 \\ 17\ne13 \end{gathered}[/tex]
This point does not lie on the circle.
(4, 3)
[tex]\begin{gathered} (4-2)^2+(3)^2=13 \\ 4+9=13 \\ 13=13 \end{gathered}[/tex]
This point does lie on the circle.
(-2, 1)
[tex]undefined[/tex]
