Given data
*The initial speed of the rock is u = 0 m/s
*The given time is t = 6.00 s
*The value of the acceleration due to gravity is g = -9.8 m/s^2
The formula for the distance traveled by the rock is given by the equation of motion as
[tex]d=ut+\frac{1}{2}gt^2[/tex]
Substitute the known values in the above expression as
[tex]\begin{gathered} d=(0)(6.0)+\frac{1}{2}(-9.8)(6.0)^2 \\ =-176.4\text{ m} \\ \approx-176\text{ m} \end{gathered}[/tex]
