contestada

Question 3 of 5What could you do to increase the electric force between two chargedparticles by a factor of 16?A. Reduce one particle's charge by a factor of 16.B. Reduce one particle's charge by a factor of 4.C. Increase one particle's charge by a factor of 16.O D. Increase one particle's charge by a factor of 4.

Question 3 of 5What could you do to increase the electric force between two chargedparticles by a factor of 16A Reduce one particles charge by a factor of 16B R class=

Respuesta :

Explanation

the force between 2 charges is given by the formula:

[tex]\begin{gathered} F=\frac{Kq_1q_2}{r^2} \\ where \\ q_i\text{ is the charge on object i} \\ r\text{ is the distance between the charges} \\ K=Coulomb\text{ constant=8.9875*10}^9N*\frac{m^2}{c^2} \end{gathered}[/tex]

then,we can check every option and compare the result to the original, hence

Step 1

a)option A

reduce one particle's charge by a factor of 16

so

[tex]q^{\prime}_1=\frac{q_1}{16}[/tex]

now, replace

[tex]\begin{gathered} F=\frac{Kq_1q_2}{r^2} \\ F_A=\frac{K\frac{q_1}{16}q_2}{r^2}=\frac{1}{16}\frac{Kq_1q_2}{r^2} \\ F_A=\frac{1}{16}(original) \\ F_A=\frac{1}{16}\frac{Kq_1q_2}{r^2} \end{gathered}[/tex]

therefore, option A works

Step 2

Otras preguntas