Answer
598 mmHg
Explanation
Given
Volume of the gas = 777 mL
Initial temperature, T₁ = 318 K
Initial pressure, P₁ = 299 mmHg
Since the temperature is double, then the final temperature = 2 x 318 K = 636 K
What to find:
The final pressure of the gas when its temperature is doubled.
Step-by-step solution:
Since the volume remains constant, then the final pressure of the gas can be calculated using Amonton's law formula below:
[tex]\begin{gathered} \frac{P_1}{T_1}=\frac{P_2}{T_2} \\ \\ \Rightarrow P_2=\frac{P_1T_2}{T_1} \end{gathered}[/tex]Putting the values of the parameters into the formula, we have
[tex]P_2=\frac{299mmHg\times636K}{318K}=598\text{ }mmHg[/tex]The final pressure of the gas when its temperature is doubled is 598 mmHg
