Given there is no friction, the law of conservation of energy can be applied. This is:
[tex]\Delta E=0[/tex]For our case, the energy in the beginning will be simply potential, and by the end will be only kinetic. We can write this as:
[tex]mgh=\frac{mv^2}{2}\Rightarrow h=\frac{v^2}{2g}[/tex]For our case, this will be:
[tex]h=\frac{6^2}{2*10}=1.8m[/tex]Thus, the hill has 1.8m
