(5) Solve;
[tex]\begin{gathered} \frac{-x}{4}=8 \\ \text{Multiply both sides by 4 and you'll have,} \\ \frac{-x}{4}\times\frac{4}{1}=\frac{8}{1}\times\frac{4}{1} \\ On\text{ the left side, the 4 cancels out each other} \\ \text{Therefore,} \\ -x=8\times4 \\ -x=32 \\ \text{Multiply both sides by -1} \\ -x(-1)=32(-1) \\ x=-32 \end{gathered}[/tex]Note that negative x times negative 1 results in a positive answer, that is positive x
(6) Solve
[tex]\begin{gathered} \frac{x+2}{5}=4 \\ \text{Multiply both sides of the equation by 5, and you'll have} \\ (\frac{x+2}{5})\times\frac{5}{1}=4\times5 \\ \text{Just like the previous solution, the 5 cancels out each other} \\ \text{Therefore, you now have,} \\ x+2=20 \\ \text{Subtract 2 from both sides of the equation} \\ x+2-2=20-2 \\ x+0=18 \\ x=18 \end{gathered}[/tex]