A chemist mixes a 25% boric acid solution with a 50% boric acid solution to produce a 40% boric acid solution. How much of each solution is required to obtain a total of thirty liters of the 40% boric acid.

Respuesta :

Notation

x= represent the volume for the 25% boric acid

y= represent the volume for the 50% boric acid

Solution

We can set up the following system of equationa. The first one for the boric acid:

[tex]0.25x+0.50y=30\cdot0.40=12[/tex]

The second equation for the total volume is given by:

[tex]x+y=30[/tex]

Let's solve for this last question x and we got: x= 30-y and if we replace in the first equation we got:

[tex]0.25(30-y)+0.5y=12[/tex]

And solving for y we got:

[tex]7.5-0.25y+0.5y=12[/tex][tex]y=\frac{12-7.5}{0.25}=18[/tex]

And finally solving for x we got:

[tex]x=30-18=12[/tex]

So we need 12 L of boric acid at 25% and 18 L of boric acid at 50%