[tex]\frac{2(x+8)}{x+9}[/tex]
Explanation:
Canceling out terms:
[tex]\frac{x^2+6x-16}{x^2+2x-8}=\frac{x+8}{x+4}[/tex]
Rewriting the equation:
[tex]\begin{gathered} \frac{x+8}{x+4}*\frac{2x+8}{x+9}=\frac{(x+8)(2x+8)}{(x+4)(x+9)}=\frac{(x+8)2(x+4)}{(x+4)(x+9)}=\frac{2(x+8)}{(x+9)} \\ \end{gathered}[/tex]
