Solution
For this case we have the following expression:
[tex]\sum ^{10}_{i=1}2i^2+4i-5[/tex]
Then we can replace and we have:
[tex]2\cdot\frac{10(10+1)(2\cdot10+1)}{6}+4\cdot\frac{10(10+1)}{2}-5\cdot10=2\cdot385+4\cdot55-50[/tex]
Solving we have:
770+ 220 -50= 940
